- Subtract 1 from the number.
- Square the difference. (Squaring of such number is easy as it ends in ‘0’)
- Add the difference twice to its square.
- Add 1.
Example: If the number to be squared is 61
1.
Subtract 1=> 61 - 1 = 60.
2.
Square the difference => 60 × 60 =
3600.
3.
Add the difference twice to its square
=> 3600 + 60 + 60 = 3720.
4.
Add 1 => 3720 + 1 = 3721.
So, 612
= 3721
812
=?
1)
81 - 1 = 80 (Subtract 1).
2)
802 = 6400 (square the
difference).
3)
6400 + 80 + 80 = 6560 (add the
difference twice to its square).
4)
6560 + 1 = 6561 (add 1)
So, 812
= 6561
If
the number to be squared is a 3-digit number, let’s say 121
1)
121 - 1 = 120 (Subtract 1).
2)
1202 = 14400 (square the
difference).
3)
14400 + 120 + 120 = 14640 (add the
difference twice to its square).
4)
14640 + 1 = 14641 (add 1)
So, 1212
= 14641
2512
=?
1)
251 - 1 = 250
2)
2502 = 62500
3)
62500 + 250 + 250 = 63000
4)
63000 + 1 = 63001
Ref. http://faster-maths.blogspot.com/2013/05/squaring-numbers-ending-in-1.html#.UadByNjKWVo
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